Topic  1 How can we describe the way things move?

 

In the exam you need to know how to:

  • to construct distance-time graphs for a body moving in a straight line when the body is stationary or moving with a constant speed;

  • to construct velocity-time graphs for a body moving with a constant velocity or a constant acceleration.

  • to calculate the speed of a body from the slope of a distance-time graph (HT only)

  • to calculate the acceleration of a body from the slope of a velocity-time graph (HT only)

  • to calculate the distance travelled by a body from a velocity-time graph. (HT only)

You need to know that:

  • The slope of a distance-time graph represents speed.

  • The velocity of a body is its speed in a given direction.

  • The acceleration of a body is given by:

acceleration (metre/second squared), m/s2 = change in velocity (metre/second, m/s)

                                                           time taken for change (second, s)

  • The slope of a velocity-time graph represents acceleration.

  • The area under a velocity-time graph represents distance travelled.

 

Key Words:

Speed

Distance

Time

Acceleration

Speed-time graph

Distance-time graph

 

Distance, Speed, and Time

Linear motion describes how objects travel in a straight line.  There are three quantities that we can measure:

You will have used the familiar equation:

 

Learn this for the exam:

Speed (m/s) = distance (m)

                       time (s)

 

 

In triangle form:

 

 

 

 

 

 

 

 

 

 

 

In these notes we will use SI units (m/s) although you can use the formula with km and hours, or miles per hour.  Some useful conversions are:

Question 1.  A runner completes a 100 m race in 9.8 seconds.  What is her average speed?  ANSWER

 

Velocity is speed in a given direction, e.g. 4 m/s from left to right.  This example will show the difference.  Suppose the runner travels 63 m by running round the track.  If you look at the straight line distance between A and B, you will see that it is 40 m.  The runner's velocity will be given by

 

velocity = straight line distance from A to B ÷ time

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

Question 2:  A runner runs half way round the race track above.  He runs a total distance of 63 metres at a speed of 8 m/s.

(a) What time does he take?

(b) What is his velocity from A to B?  (It is NOT 8 m/s)    ANSWER

 

Velocity is NOT a posh word for speed.

 

 

Acceleration

Acceleration is the rate at which speed changes:

The units for acceleration look strange - metres per second squared (m/s2).  It is easier to say this as "metres per second every second".

 

The equation that links speed and acceleration is:

 

Learn this for the exam:

acceleration (m/s2) = change in speed (m/s)

                      time (s)

 

 

In triangle form:

 

 

 

 

 

 

 

 

 

 

 

 

 

The physics codes are:

The change in speed can be worked out easily:

 

Change in speed = speed at end - speed at start

 

Worked Example

60 mph is 27 m/s.  What is the acceleration of a car whose 0 - 60 figure is 13.5 s?
First of all work out the change in speed.

Ds = 27 m/s - 0 m/s = 27 m/s

Acceleration is now worked out:

a = 27 m/s ÷ 13.5 s = 2.0 m/s2

 

Question 3:  A car accelerations from 20 m/s to 40 m/s in 15 s.  What is its acceleration?  ANSWER

If the speed at the end is lower than the speed at the start, the acceleration is negative.

Question 4:  A car slows down from 30 m/s to 15 m/s in 10 s.  What is its acceleration?

ANSWER

 

 

Motion Graphs

We can represent the movement of objects using a graph, usually plotting time on the x-axis (horizontal) and the speed or distance on the y-axis (vertical).

 

 

Distance-Time Graph

Let us have a look at a distance time graph of a cyclist:

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

Between A and B the cyclist is cycling at a constant speed.  The gradient (slope) of the graph gives us the speed.  Since the gradient is a straight line, the speed is constant.

 

Question 5:  What is happening between B and C, and C and D?  ANSWER

 

Question 6:  How would you tell from a distance-time graph that an object was accelerating?  ANSWER

 

 

Speed-Time Graph

The graph below shows a train accelerating from a station along a straight and level track to a maximum speed and slowing down to a stop at the next station.  The easiest way to show this is with a speed time graph.

 

Acceleration is the gradient of the speed-time graph.

From the graph,

Distance is the area under the speed-time graph.  To work out the total distance, we would add the areas of:

At GCSE acceleration is uniform, which means that the speed [velocity] is changing at a constant rate.    This is shown by a straight line on a speed time graph. 

A tachograph on a lorry is a speed time graph.  It is a very accurate speedometer (in kilometres per hour) which plots a speed time graph on a small circular piece of paper.

       

The instrument plots a trace which you can see on the card.  There are strict rules on the hours that drivers of buses and lorries may work.  The tachograph records when the driver is driving, is at work not driving, is taking breaks, and resting.  The tachograph is not new; instruments for recording speed have been used on railways for over a century.

 

For more, visit http://www.digitaltachograph.gov.uk/

 

Working Out Speed or Acceleration from A Motion Graph (HT ONLY)

You may well have to plot a distance time graph or a speed time graph.  Click HERE for some basic guidance on drawing graphs.

 

To work out the distance from a speed time graph, you need to work out the area.  If the graph consists of rectangles and triangles, it's simple.  Work out the area of each shape and add them together. 

 

If the graph is complicated, you can get a good idea of the area by counting the squares.  If more than half a square is under the graph, count it.  If less than half, ignore it.  Generally you get pretty close to the area. 

 

(There is a mathematical trick called calculus that allows us to work out the area under a graph without counting squares, but that is way beyond what you need to know.)

 

 

Question 7 Use the information below in the question.  The train's motion is that described in the graph above.

What is:

a)      The acceleration between O and A

b)      The acceleration between B and C

c)      The distance covered while the train is at constant speed

d)      The total distance.

     e)   The average speed?  

ANSWER

To work out the gradient of a graph:

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

Question 8.  What is the acceleration of the car whose motion is shown in the graph below?  ANSWER

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

Summary

  • Speed = distance ÷ time

  • Velocity is speed in a certain direction;

  • Acceleration = change in speed ÷ time;

  • Motion can be represented in distance time or speed time graphs;

  • Gradient of the distance time graph is speed;

  • Gradient of the speed time graph is acceleration;

  • Area under the speed time graph gives distance.

 

Now try the Topic Quiz

 

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