Answer 4_9_7

Two plates are placed 15 cm apart connected to a 4500 V supply.

 

(a)    What is the strength of the uniform field between the plates?

(b)   What is the force acting on a 6 nC test charge between the plates?         

 

(a) E = V/d = 4500 V ¸ 0.15 m (P) = 30 000 V/m (P)

 

 

 

(b) E = F/Q Þ F = EQ = 30 000 V/m ´ 6.0 ´ 10-9 C (P) = 1.8 ´ 10-4 N (P)

 

 

 

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