Topic
6 Elastic Properties of Solid
Materials
| Key Words Density, Elastic, Plastic, Stress, Strain, Young modulus |
We
will study how materials behave under compression
(squashing) forces and tension
(stretching) forces. Scientists
need to know how materials behave so that they can assess how suitable a
particular material is to a particular job.
Density
Density is mass per unit volume. Density, mass, and volume are linked by a simple relationship:


SI
Units for density are kg/m3.
In some texts, you will find some densities given in g/cm3.
It is important that you use the SI
units otherwise formulae will not work.
To convert you will need the following conversion:
1
g/cm3 = 1000 kg/m3
| Question 1 |
|
ANSWER | ||||||||
| Question 2 |
What is the volume of 100 g of Mercury of which the density is 13 600 kg m-3? |
ANSWER | ||||||||
| When is a plastic not a plastic? |
If we load a
spring, we find that the extension (code e)
or stretch is proportional to the force
(code F). If we double the
force, we double the stretch.
F
µ
e
Þ
F = ke
The constant of proportionality is called the spring constant and is measured in newtons per metre (N/m).
Bear trap: Remember to convert the extension into metres and the load into Newtons before working out the spring constant.
We can plot this as a graph:

We can see that the graph is a straight line and that the gradient gives us the spring constant. That is why we have the extension on the horizontal axis.
The same is true if we apply a squashing force.
If we stretch a
wire, the amount it stretches by depends on:
If we have two of the same material and length, it is clear that the thicker wire will stretch less for a given load. We make this a fair test by using the term tensile stress which is defined as the tension per unit area normal to that area. The term normal means at 90o to the area.
We can also talk of the compression force per unit area, i.e. the pressure.
Stress
= Load (N) = F
area (m2) A
In some text books you may see stress given the code s (sigma, a Greek letter 's').
You
will have met the expression F/A before.
It is, of course, pressure, which implies a
squashing force. A stretching force gives an expression of the same kind.
Units are newtons per square metre (N/m2) or Pascals
(Pa).
You
must always convert areas to square metres for
this equation to work. Remember that radii will often be given in mm or
cm. This is a common bear trap.
1 mm2 = 1 x 10-6 m2
Therefore if you get an area of 10-2 you probably have forgotten to do the conversion to square metres.
| Question 4 |
Find the area of a wire of diameter 0.75 mm in m2. |
ANSWER |
If we have a wire
of the same material and the same diameter, it doesn’t take a genius to see
that the wire will stretch more for a given load if it is longer.
To take this into account, we express the extension as a ratio of the
original length. We call this the tensile
strain which we define as the extension per
unit length.
Strain = extension (m)
= e
original length (m) l
There are no units for strain; it’s just a number. It can sometimes be expressed as a percentage.
You will find that the same is true for when we compress a material.
| Question 5 |
What is the strain of a 1.5 m wire that stretches by 2 mm if a load is applied? |
ANSWER |
Elastic
Strain Energy
When we stretch a
wire, we have to do a job of work on the wire.
We are stretching the bonds between the atoms.
If we release the wire, we can recover that energy, which is called the
elastic
strain energy. Ideally we
recover all of it but in reality a certain amount is lost as heat.
This lost energy is called hysteresis.
The energy is the area under the force-extension graph.


This result can be obtained using the process of integration, which is part of the branch of mathematics called calculus. You are not expected to know this for AS, although you will be if you study Physics at University. All we need to say here is that the energy is the area of the triangle.
| Question 6 |
What is the elastic strain energy contained in a copper wire of diameter 0.8 mm that has stretched by 4 mm under a load of 400 N? |
ANSWER |
| Question 7 |
Which two bits of data are irrelevant in the question above? |
ANSWER |
Stress-Strain
Curves
Stress-strain graphs are really a development of force-extension graphs, simply taking into account the factors needed to ensure a fair test. A typical stress-strain graph looks like this:

We
can describe the details of the graph as:
P
is the limit of proportionality,
where the linear relationship between stress and strain finishes.
E
is the elastic limit.
Below the elastic limit, the wire will return to its original shape.
Y is the yield point, where plastic deformation begins. A large increase in strain is seen for a small increase in stress.
UTS
is the ultimate tensile stress,
the maximum stress that is applied to a wire without its snapping.
It is sometimes called the breaking
stress. Notice that beyond
the UTS, the force required to snap the wire is less.
S
is the point where the wire snaps.
We can draw stress-strain graphs of materials that show other properties.

Curve
A shows a brittle
material. This material is
also strong because there is little strain for a high stress.
The fracture of a brittle material is sudden and catastrophic, with
little or no plastic deformation. Brittle
materials crack under tension and the stress increases around the cracks.
Cracks propagate less under compression.
Curve
B is a strong
material which is not ductile. Steel wires stretch very little,
and break suddenly. There can be a lot of elastic strain energy in a
steel wire under tension and it will “whiplash” if it breaks. The
ends are razor sharp and such a failure is very dangerous indeed.
Curve
C is a ductile
material
Curve
D is a plastic
material. Notice a very large strain for a small stress. The
material will not go back to its original length.

Stress strain graphs are used extensively by material scientists. Machines like this are used:


The
Young Modulus
The
Young Modulus is defined as the
ratio of the tensile stress and the tensile strain.
Young modulus = tensile stress
tensile strain
tensile stress = force =
F
area A
tensile strain = ___extension __
= e
original length l
So we can write:

Units
for the Young Modulus are Pascals (Pa) or newtons
per square metre (Nm-2).
The
Young Modulus describes pulling forces.
We can link the Young Modulus to a stress strain graph.

The Young Modulus is the gradient of the stress-strain graph for the region that obeys Hooke’s Law. This is why we have the stress on the vertical axis when we would expect the stress to be on the horizontal axis.
The area under the stress strain graph is the strain energy per unit volume (joules per metre3).
Strain energy per unit volume = 1/2 stress x strain.
The units arise because stress is in Nm-2 and strain is mm-1 (NOTE: This unit here is not "millimetres to the minus one", but metres per metre which mean no units).
Nm-2 x mm-1 = Nm m-3. Nm is joules, hence Jm-3
| A wire made of a particular material is loaded with a load of 500 N. The diameter of the wire is 1.0 mm. The length of the wire is 2.5 m, and it stretches 8 mm when under load. What is the Young Modulus of this material? |

| Presentation | Solid Materials | ||||
| Now try Topic 6 Test | Topic 6 Quiz | Home | Physics AS | Module 3 | |