Topic 6 Elastic Properties of Solid Materials

Key Words

Density, Elastic, Plastic, Stress, Strain, Young modulus

We will study how materials behave under compression (squashing) forces and tension (stretching) forces.  Scientists need to know how materials behave so that they can assess how suitable a particular material is to a particular job.

Density

Density is mass per unit volume.  Density, mass, and volume are linked by a simple relationship:

SI Units for density are kg/m3.  In some texts, you will find some densities given in g/cm3.  It is important that you use the SI units otherwise formulae will not work.  To convert you will need the following conversion:

1 g/cm3 = 1000 kg/m3

  Watch out for this bear trap.

 

Question 1

 What are the following densities in kg m-3?                                              

 

1.29 g cm-3

 

 

7.6 g cm-3

 

 

19.6 g cm-3

 

ANSWER
Question 2

What is the volume of 100 g of Mercury of which the density is 13 600 kg m-3?

ANSWER

Click HERE to see some important definitions.  You will see these in the text books.

Question 3

When is a plastic not a plastic?

ANSWER

 

 

Hooke’s Law

If we load a spring, we find that the extension (code e) or stretch is proportional to the force (code F).  If we double the force, we double the stretch.

   F µ e

Þ F = ke

The constant of proportionality is called the spring constant and is measured in newtons per metre (N/m). 

Bear trap:  Remember to convert the extension into metres and the load into Newtons before working out the spring constant.

We can plot this as a graph:

We can see that the graph is a straight line and that the gradient gives us the spring constant.  That is why we have the extension on the horizontal axis.

The same is true if we apply a squashing force.

 

Stress and Strain

If we stretch a wire, the amount it stretches by depends on:

If we have two of the same material and length, it is clear that the thicker wire will stretch less for a given load.  We make this a fair test by using the term tensile stress which is defined as the tension per unit area normal to that area.  The term normal means at 90o to the area. 

We can also talk of the compression force per unit area, i.e. the pressure

Stress = Load (N) = F                                             

           area (m2)   A

In some text books you may see stress given the code s (sigma, a Greek letter 's').

You will have met the expression F/A before.  It is, of course, pressure, which implies a squashing force.  A stretching force gives an expression of the same kind.  Units are newtons per square metre (N/m2) or Pascals (Pa).

                                     1 Pa = 1 N/m2

You must always convert areas to square metres for this equation to work.  Remember that radii will often be given in mm or cm.  This is a common bear trap.

1 mm2 = 1 x 10-6 m2

Therefore if you get an area of 10-2 you probably have forgotten to do the conversion to square metres.

 

Question 4

Find the area of a wire of diameter 0.75 mm in m2

ANSWER

If we have a wire of the same material and the same diameter, it doesn’t take a genius to see that the wire will stretch more for a given load if it is longer.  To take this into account, we express the extension as a ratio of the original length.  We call this the tensile strain which we define as the extension per unit length.

                        Strain = extension (m)               = e

                                   original length (m)            l

 

There are no units for strain; it’s just a number.  It can sometimes be expressed as a percentage. 

 

You will find that the same is true for when we compress a material.

 

Question 5

What is the strain of a 1.5 m wire that stretches by 2 mm if a load is applied?

ANSWER

Elastic Strain Energy

When we stretch a wire, we have to do a job of work on the wire.  We are stretching the bonds between the atoms.  If we release the wire, we can recover that energy, which is called the elastic strain energy.  Ideally we recover all of it but in reality a certain amount is lost as heat.  This lost energy is called hysteresis. 

The energy is the area under the force-extension graph.

So we can use this result to say:

This result can be obtained using the  process of integration, which is part of the branch of mathematics called calculus.  You are not expected to know this for AS, although you will be if you study Physics at University.  All we need to say here is that the energy is the area of the triangle.

Question 6

What is the elastic strain energy contained in a copper wire of diameter 0.8 mm that has stretched by 4 mm under a load of 400 N? 

ANSWER
Question 7

Which two bits of data are irrelevant in the question above?

ANSWER

 

Stress-Strain Curves

Stress-strain graphs are really a development of force-extension graphs, simply taking into account the factors needed to ensure a fair test.  A typical stress-strain graph looks like this:

We can describe the details of the graph as:

We can draw stress-strain graphs of materials that show other properties.

  Rubber has a strange force-extension graph.

Stress strain graphs are used extensively by material scientists.  Machines like this are used:

This will prevent failures like this.

The Young Modulus

The Young Modulus is defined as the ratio of the tensile stress and the tensile strain.  

  So we can write:

            Young modulus = tensile stress

                                      tensile strain

  We know that

            tensile stress = forceF

                                  area      A

  and that

            tensile strain =  ___extension __   = e

                                   original length        l

So we can write:

Units for the Young Modulus are Pascals (Pa) or newtons per square metre (Nm-2).

The Young Modulus describes pulling forces. 

We can link the Young Modulus to a stress strain graph.

The Young Modulus is the gradient of the stress-strain graph for the region that obeys Hooke’s Law.  This is why we have the stress on the vertical axis when we would expect the stress to be on the horizontal axis.

The area under the stress strain graph is the strain energy per unit volume (joules per metre3).

Strain energy per unit volume = 1/2 stress x strain.

The units arise because stress is in Nm-2 and strain is mm-1 (NOTE: This unit here is not "millimetres to the minus one", but metres per metre which mean no units).

        Nm-2 x mm-1 = Nm m-3.  Nm is joules, hence Jm-3

Question 8

A wire made of a particular material is loaded with a load of 500 N.  The diameter of the wire is 1.0 mm.  The length of the wire is 2.5 m, and it stretches 8 mm when under load.  What is the Young Modulus of this material?

ANSWER

Presentation Solid Materials
Now try Topic 6 Test Topic 6 Quiz Home Physics AS Module 3