Topic 7 Momentum
| Key Words Momentum, Mass, Velocity, Collision, Conservation, Impulse |
Momentum
is the product between mass and velocity.
Being a vector quantity, it
has a direction, and the direction is
very important when doing momentum calculations. Momentum is not a thing
that we can see, but it does explain many things that go on in physics.

Units are kilogram metres per second (kg m/s) or newton seconds (Ns). We can show that the units are the same.
| What is the value of the momentum of a 10 kg ball running down a bowling alley at a speed of 5 m/s? |
In the example above, we only looked at the value of the momentum. This is why we used the word speed. It is very important to make sure that you pay attention to the signs when doing momentum calculations.
Think of a ball bouncing off a wall. It leaves the wall at the same speed as before. Let’s call going from right to left negative, and going from left to right positive.

| Question 2 | Can you show that the change in momentum is +2mv? | ANSWER |
| Question 3 | The ball has a mass of 200 g, and the value of its velocity throughout remains 6 m/s. What is the change in momentum? |
An
important principle:
Momentum
is always conserved in collisions.
If
objects bounce off each other, the collision is elastic.
If the total kinetic energy is the same (conserved)
at the end as it is at the start, then the collision is perfectly elastic.
The rebound of particles against each other tends to be perfectly
elastic. A tennis ball bouncing
off the floor is not perfectly elastic as it can lose up to 25 % of its kinetic
energy in doing so.
If
some kinetic energy is lost, converted into heat or light, then the collision is
inelastic.
Think about two objects travelling in the same direction. The table below shows the properties of the objects:
|
Property |
Large
Object |
Small
Object |
|
Mass |
M |
m |
|
Initial
velocity |
u1 |
u2 |
|
Final
velocity |
v1 |
v2 |

There
are two important principles here:
1.
Conservation
of momentum:
Total
momentum before = total momentum after
Mu1
+ mu2 = Mv1 + mv2
Total
energy before = total energy after
½Mu12
+ ½mu22 =
½Mv12
+ ½mv22 + E
The
term E is the energy that is lost
in the collision. In a perfectly
elastic collision E = 0.
When doing momentum calculations, always be careful about the directions you are using.
| Question 4 |
The diagram shows two cars at a fairground, before and after bumping into each other. One car and driver has a total mass of 500 kg, while the other car and driver has a total mass of 400 kg.
(a) What is (i) the total kinetic energy before the collision; (ii) the total kinetic energy after the collision. (iii) the total loss in kinetic energy. (b) Is this an elastic collision? Explain your answer.
|
ANSWER |
| Question 5 |
A second collision is shown below:
What is the speed of the 500 kg car after the collision?
|
ANSWER |
| Question 6 |
A bullet of mass 45 g is travelling horizontally at 400 m/s when it strikes a wooden block of mass 16 kg suspended on a string so that it can swing freely. The bullet is embedded in the block.
Calculate: a) The velocity at which the block begins to swing; b) The height to which the block rises above its initial position; c) How much of the bullet’s kinetic energy is converted to internal energy.
|
ANSWER |
This question is a typical question you will find in the exam. It is often called synoptic, because it tests several different concepts at the same time. At A2 you will do a synoptic paper that has questions that can combine parts from several different modules. At AS you will only be asked on things that appear in that module.
The
change in momentum is called the impulse and is given the physics code Dp.
We can define Newton’s Second Law in terms of change of momentum:
Force = change in momentum
time interval

Þ
Impulse (Ns) = Force
(N) x time interval (s)
In
code:
Dp
= FDt
If we plot a force time graph, we can see that impulse is the area under the graph.

In this graph, both impulses are the same. The forces and time intervals are different.
| Can you explain how the formula F = Dp/Dt is consistent with Newton II? |
Impulse is the physics phenomenon that explains how a ball behaves when kicked or hit with a bat. It also has important implications in road safety. When a car is involved in a collision, we want the impulse to occur over a longer time interval to reduce the forces involved.
|
a) Calculate the average force exerted on the driver by his seat belt. b) Compare this force to his weight and hence work out the “g-force” c) Comment on the likelihood of serious injury. |

| Presentations | Momentum | Collisions | Impulse |
| Now try Topic 7 Test | Home | Module 2 | Physics AS |