Topic 7  Momentum

Key Words

Momentum, Mass, Velocity, Collision, Conservation, Impulse

Momentum is the product between mass and velocity.  Being a vector quantity, it has a direction, and the direction is very important when doing momentum calculations.  Momentum is not a thing that we can see, but it does explain many things that go on in physics.

  Momentum (kg m/s) = mass (kg) x velocity (m/s)

 

Units are kilogram metres per second (kg m/s) or newton seconds (Ns).  We can show that the units are the same.

Question 1

What is the value of the momentum of a 10 kg ball running down a bowling alley at a speed of 5 m/s?

ANSWER

In the example above, we only looked at the value of the momentum.  This is why we used the word speed.   It is very important to make sure that you pay attention to the signs when doing momentum calculations.

Think of a ball bouncing off a wall.  It leaves the wall at the same speed as before.  Let’s call going from right to left negative, and going from left to right positive.

Question 2 Can you show that the change in momentum is +2mv? ANSWER
Question 3 The ball has a mass of 200 g, and the value of its velocity throughout remains 6 m/s.  What is the change in momentum?

ANSWER

 

Conservation of Momentum

An important principle:

  The total momentum of a system remains constant provided that no external forces act on the system. 

  This has important implications in the study of collisions.  In simple terms, we can say that the total momentum before =  total momentum after.  The key thing is that share of the momentum may change.

 

Collisions

Momentum is always conserved in collisions.

If objects bounce off each other, the collision is elastic.  If the total kinetic energy is the same (conserved) at the end as it is at the start, then the collision is perfectly elastic.  The rebound of particles against each other tends to be perfectly elastic.  A tennis ball bouncing off the floor is not perfectly elastic as it can lose up to 25 % of its kinetic energy in doing so.

If some kinetic energy is lost, converted into heat or light, then the collision is inelastic.

Think about two objects travelling in the same direction.  The table below shows the properties of the objects:

Property

Large Object

Small Object

Mass

M

m

Initial velocity

u1

u2

Final velocity

v1

v2

  We can show this as a diagram:

There are two important principles here:

1.      Conservation of momentum:

Total momentum before = total momentum after

Mu1 + mu2 = Mv1 + mv2

  1. Energy is conserved:

Total energy before = total energy after

½Mu12 + ½mu22 = ½Mv12 + ½mv22 + E

The term E is the energy that is lost in the collision.  In a perfectly elastic collision E = 0.

When doing momentum calculations, always be careful about the directions you are using.

 

Question 4

The diagram shows two cars at a fairground, before and after bumping into each other.  One car and driver has a total mass of 500 kg, while the other car and driver has a total mass of 400 kg.

(a)  What is    (i) the total kinetic energy before the collision;

                    (ii) the total kinetic energy after the collision.

                         (iii) the total loss in kinetic energy.

(b) Is this an elastic collision?  Explain your answer. 

 

ANSWER
Question 5

A second collision is shown below:

What is the speed of the 500 kg car after the collision?

 

ANSWER
Question 6

A bullet of mass 45 g is travelling horizontally at 400 m/s when it strikes a wooden block of mass 16 kg suspended on a string so that it can swing freely.  The bullet is embedded in the block.  

Calculate:

a)      The velocity at which the block begins to swing;                                              

b)      The height to which the block rises above its initial position;                  

c)      How much of the bullet’s kinetic energy is converted to internal energy. 

 

ANSWER

 

This question is a typical question you will find in the exam.  It is often called synoptic, because it tests several different concepts at the same time.  At A2 you will do a synoptic paper that has questions that can combine parts from several different modules.  At AS you will only be asked on things that appear in that module.

 

 
Impulse

The change in momentum is called the impulse and is given the physics code Dp.  We can define Newton’s Second Law in terms of change of momentum:

                                    Force = change in momentum

                                                      time interval                                                

                                                                    

                                    Þ Impulse (Ns) = Force (N) x time interval (s)

In code:

Dp = FDt

If we plot a force time graph, we can see that impulse is the area under the graph.

In this graph, both impulses are the same.  The forces and time intervals are different.

Question 7

 Can you explain how the formula F = Dp/Dt is consistent with Newton II?

ANSWER

Impulse is the physics phenomenon that explains how a ball behaves when kicked or hit with a bat.  It also has important implications in road safety.  When a car is involved in a collision, we want the impulse to occur over a longer time interval to reduce the forces involved.

Question 8

A car is involved in a collision in which it is brought to a standstill from a speed of 24 m/s.  The driver of mass 85 kg is brought to rest by his seat belt in a time of 400 ms.

a)    Calculate the average force exerted on the driver by his seat belt.                                  

b)    Compare this force to his weight and hence work out the “g-force”                               

     c)   Comment on the likelihood of serious injury.

ANSWER

 

Presentations Momentum Collisions Impulse
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