Topic 1 - Motion
| Key Words Speed, distance, velocity, displacement, acceleration, time |
This topic looks at linear motion, i.e. motion in a straight line.
Distance
is how far you travel between any two points by any route.
It is a scalar quantity.
Displacement
is the minimum “as the crow flies” distance between two points.
It is a vector quantity,
so it has direction.
Speed
is
how fast you go, the rate of change
of distance.
Velocity
is rate of change of displacement.
It must have a direction.
Acceleration
can be used as both a vector and a scalar quantity. It is the rate of
change of speed or velocity.
speed (m/s) = distance (m)
time(s)

velocity (m/s) = displacement (m)
time (s)
We also know acceleration as:

The picture below shows the difference between distance and displacement.

Suppose we have two towns A and B 10 km apart but either side of a hill. They are joined by a railway line that is straight, and goes through the hill in a tunnel. The road goes round the hill and the total journey distance is 25 km.
So the distance is 25 km. The displacement (the straight-line distance in a particular direction) between A and B is 10 km due East.
If we go from A to B and back again, the distance is 50 km, but the displacement is 0.
| Why is the displacement 0? | ||
| A runner accelerates at a rate of 4 ms-2 to her maximum speed of 9.6 m/s. What is the time taken for her to reach this speed? |
Information and Communication Technology (Computers) can be used to demonstrate the motion of a vehicle. Sensors (light gates or ultrasonic detectors) are connected to a computer and the computer will record the data at time intervals. The computer will plot a graph of the motion.
Click HERE to see some important definitions.
Graphical Interpretation of Acceleration
We can represent the movement of objects using a graph, usually plotting time on the x-axis (horizontal) and the speed or distance on the y-axis (vertical).
Consider a train accelerating from a station along a straight and level track to a maximum speed and slowing down to a stop at the next station. The easiest way to show this is with a speed time graph.

Acceleration
is the gradient of the speed-time graph.
From the
graph,
between
O and A, the train is accelerating;
between
A and B, the train travels at a constant speed;
between
B and C, the train slows down. Slowing down can also be called negative
acceleration, or deceleration. It is given a minus sign.
Distance is the area under the speed-time graph. To work out the total distance, we would add the areas of:
triangle OAX;
rectangle ABXY;
triangle BCY.
| Question 3 |
Use the information below in the question. The train's motion is that described in the graph above.
What is:
a)
b) The acceleration between B and C c) The distance covered while the train is at constant speed d) The total distance. e) The average speed? |
The corresponding distance time graph is like this:

We can work out the speed at any instant by measuring the gradient of the distance time graph. The curved line tells us that the speed is changing.
Acceleration is usually uniform, which means that the speed [velocity] is changing at a constant rate. This is shown by a straight line on a speed time graph. However in many real life situations acceleration is not constant. Therefore the graph is not a straight line:

Good graphical skills are important in Physics. Click HERE if you need to review graphs.
| Presentation | Motion Graphs |
| Now go on to Equations of Motion | Back to Module 2 |