.Answer 7_3_6
(a) The equation to use is:
.
1.01 × 105 Pa x (4.25 × 10-4 m3)1.40 = 1.70 × 105 Pa x V21.40
1.01 × 105 Pa x 1.90 x 10-5 = 1.70 × 105 Pa x V21.40
V21.40 = 1.01 × 105 Pa x 1.90 x 10-5 = 1.13 x 10-5
1.70 × 105 Pa
V2 = (1.13 x 10-5)1/1.4 = 2.94 x 10-4 m3
(b) Use:
1.01 × 105 Pa x 4.25 × 10-4 m3 = 1.70 × 105 Pa x 2.94 x 10-4 m3
296 T2
T2 = 296 x 1.70 × 105 Pa x 2.94 x 10-4 m3
1.01 × 105 Pa x 4.25 × 10-4 m3
T2 = 344 K
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