Answer 6_7_3

(a) Power = VI = 100 000 V × 0.04 A = 4000 W

(b) Number of electrons per sec = 0.04 ÷ 1.6 × 10^-19 = 2.5 x 10¹⁷ s^-1

(c) Number of photons is about 1/100 of this, 2.5 x 10¹⁵ s^-1

(d) Photon energy = 100 000 x 1.6 x 10^-19 = 1.6 x 10^-14 J

Wavelength = hc/E = (6.63 x 10^-34 x 3 x 10⁸) ÷ 1.6 x 10^-14 = 1.24 x 10^-11 m

= 0.0124 nm

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