Mass and
Energy
| Key Words Atomic mass unit, mass defect, binding energy, fission, fusion |
|
You
are expected to: ·
Do
simple calculations on nuclear transformations; ·
Understand
the concept of mass difference and binding energy; ·
Understand
the atomic mass unit, u; ·
Convert
from one unit to another using 1 u = 931.1 MeV, E = mc2; ·
Appreciate
that E = mc2 applies to all energy changes; ·
Know
the graph of average binding energy per nucleon against nucleon number, A; ·
Understand
fission and fusion processes. |
Kilograms
are useful for measuring large masses, but like many of the SI units, on the
atomic scale they are far too big. It’s
a bit like a model maker using kilometres rather than millimetres.
The
atomic mass unit is far more
convenient to use with nuclear masses. It
uses carbon 12 as a reference and is defined as:
Exactly
1/12th the mass of a carbon 12 atom
The
relative atomic mass of an atom is
useful. It is defined as:
___Mass
of the atom ´ 12
Mass of
carbon 12 atom
The
relative atomic mass of atoms is usually very close to a whole number, which is
consistent with the idea of a nucleus made up of whole numbers of nucleons.
1
atomic mass unit (u) = 1.661 ´
10-27 kg.
The
table shows particle masses in atomic mass units. Note that the numbers are expressed to a large number of
significant figures as the changes are quite subtle.
|
Particle |
Mass
(u) |
|
Electron |
0.000549 |
|
Neutron |
1.008665 |
|
Proton |
1.007276 |
|
Hydrogen
atom (1p+ + 1 e-) |
1.007825 |
|
Helium
atom (2p+ + 2 n + 2e-) |
4.002063 |
|
a- particle (2p+ + 2 n) |
4.001505 |
We
need to be careful to distinguish between the atomic mass and the nuclear
mass.
·
The
atomic mass is the mass of an atom complete with its electrons;
·
The
nuclear mass is the mass of the nucleus alone.
To get the nuclear mass we need to take away the mass of the electrons.
| What is the nuclear mass of helium 3 (3He) of which the atomic mass is 3.016030 u? |
If
we add together the mass of an electron and the mass of a single proton, we get
the mass of a hydrogen atom. Let us do the same for a helium atom.
|
Particle |
Mass
(u) |
Number |
Total
(u) |
|
Proton |
1.007276 |
2 |
2.014552 |
|
Neutron |
1.008665 |
2 |
2.017330 |
|
Electron |
0.000549 |
2 |
0.001098 |
|
|
|
|
4.032980 |
However,
if we look in a data book, we see that the atomic mass is 4.002603
u.
There is a difference of 0.030377 u.
All
atoms are lighter than the sum of the masses of the protons, electrons, and
neutrons. This is the mass
defect, which is the difference
between the total mass of the nucleons and the measured mass of the nucleus
itself.
To
extract a proton or a neutron from the nucleus, we have to pull pretty hard.
Then we find that it will regain its missing mass.
We can use the idea of binding
energy to explain this. The binding
energy is defined as the energy released when a nucleus is assembled from
its constituent nucleons. It is equal to the energy
needed to tear the nucleus apart into its nucleons.
So
with our helium atom, the missing 0.030377 u is released when the nucleons come
together. That energy has to be put
back to split the nucleus up again.
This
brings us onto the strange idea that mass
and energy at the nuclear level are interchangeable and can be related with Einstein’s simple equation:
E = mc2
[E – energy (J); m – mass (kg); c – speed of light (m/s)]
It
is important to convert the mass from atomic mass units to kilograms.
The answer we get is in joules. We
can convert this to eV by dividing by 1.6 ´ 10-19 J/eV
| What is the binding energy of the helium atom whose mass defect is 0.030377 u? |
Joules
are not convenient units to use at the nuclear level, so we convert to electron
volts (eV) by dividing by 1.6 ´ 10-19 J/eV.
A
useful conversion factor between mass and energy is that 1 u = 931.3 MeV
Worked Example
|
Particle |
Mass
(u) |
Number |
Total
(u) |
|
Proton |
1.007276 |
3 |
3.021828 |
|
Neutron |
1.008665 |
4 |
4.03466 |
| What
is the mass defect in atomic mass units (u) and in kilograms for the lithium
nucleus which has 7 nucleons, and a proton number of 3?
What is the binding energy in J and eV?
What is the binding energy per nucleon in eV?
The nuclear mass = 7.014353 u. |
| Li has a nucleon number of 7 and a proton number of 3, which means there are 3 protons and 4 neutrons. |
| Now look up the masses for the proton and neutron from the data. These will be given to you; you are not expected to remember them. |
| Add them together to get 7.056488 u |
|
Now take away the nuclear mass from the number above to get the mass deficit. 7.056488
u - 7.014353 u = 0.042135 u |
|
Now convert to kilograms: 1 u = 1.661 ´
10-27 kg 0.042135
u × 1.661 ´ 10-27 kg = 6.9986235 × 10-29 kg |
|
Now use E = mc2 to work out the binding energy: E = 6.9986235 × 10-29 kg × (3 × 108 m/s)2 = 6.3 × 10-12 J |
| In electron volts, this is 6.3 × 10-12 J ÷ 1.6 × 10-19
eV/J = 3.9 × 107 eV = 39 MeV. |
| There are 7 nucleons so the binding energy per nucleon = 3.9 × 107
eV ÷ 7 = 5.6 × 106 eV |
| What is the mass defect in atomic mass units (u) and in kilograms for the copper nucleus which has 63 nucleons, and a proton number of 29? What is the binding energy in J and eV? What is the binding energy per nucleon in eV? The nuclear mass = 62.91367 u. |
Binding
Energy Per Nucleon
If
we know the binding energy in a nucleus, and the number of nucleons, we can work
out the binding energy per nucleon, which is the average energy needed to remove
each nucleon. The higher the
binding energy per nucleon, the more stable is the nucleus.
For helium (4He) the binding energy per nucleon is:
Binding energy per nucleon = 28.38 MeV ¸ 4 = 7.1 MeV
We
can plot a graph of binding energy per nucleon against nucleon number.

From
this graph we can see the following:
·
The vast majority of nuclides have a binding energy of 8 MeV per nucleon.
·
Helium has a particularly high value of binding energy per nucleon, much
higher than the light isotopes of hydrogen.
·
There is a trend for nuclides of nucleon numbers in multiples of 4 to be
particularly stable (i.e. have a high binding energy).
·
Fe is the most stable nuclide.
·
The largest nuclides tend to be less stable, with slightly lower binding
energies per nucleon.
Iron
has the highest binding energy per nucleon so is the most stable nucleus.
If we look at large nuclei (greater than iron), we find that the further
to the right (greater nucleon number) the less stable the nuclei.
This is because the binding energy per nucleon is getting less.
The explanation for this observation lies in that the strong nuclear
force that binds the nucleus together has a very limited range, and there is a
limit to the number of nucleons that can be crammed into a particular space.
Radioactive
Decay and Binding Energy
Radioactive
decay happens when an unstable nucleus emits radiation.
It becomes more stable. The daughter nuclei always have a higher binding
energy per nucleon
than the parent nucleus.
Let
us look at alpha decay:
Mass
of the thorium nucleus = 227.97929 u
Mass
of the radium nucleus = 223.97189 u
Mass
of the alpha particle (helium nucleus) = 4.00151 u
Mass
on the left hand side = 227.97929 u
Mass
on the right hand side = 223.97189 u + 4.00151 u = 227. 97340 u
The
right hand side has a mass defect = 227.97929 u - 227. 97340 u =
0.00589 u
The
mass defect can be written in kilograms and the energy can be expressed in
joules, but nuclear physicists use a useful little dodge.
The energy equivalence of 1 u =
931.5 MeV.
So the energy given out by this decay is:
E
= 931.5 ´ 0.00589 = 5.49 MeV.
This
is a beta decay:
|
Given this data: Mass of aluminium nucleus = 28.97330 u Mass of silicon nucleus = 28.96880 u Mass of beta particle (electron) = 0.00549 u Mass of electron antineutrino = 0 What is energy given out by the above decay in MeV? What form does it take? |
If
we look at the graph with binding energy per nucleon, we observe that the large
nuclei have a lower binding energy per nucleon. This means that they are less stable. This lack of stability is usually shown by radioactive decay,
which occurs in a predictable way. Very
rarely a large nucleus will split up spontaneously into fragments.
This splitting of the nucleus is called fission.
The
easiest way to explain this is to consider the nucleus as a “wobbly
drop”.
Nuclei are not tidy and neatly arranged rows of neutrons and protons;
they are microscopic bedlam.
The strong nuclear force acts between neighbouring nucleons.

The nucleons are not linked
with the same neighbours all the time.
Instead they are constantly swapping about.
However the enough of the nucleons linked to stop the repulsive
electromagnetic force tearing the nucleus apart.
Now we imagine the nucleus as a wobbly drop:

Now
if the nucleus gets to this shape

The nucleus flies apart in two fragments:

The
detail of the mechanism that drives this process is complicated and is based on Heisenberg’s
uncertainty principle. A similar model can be used to explain how
alpha decay works.
We
can induce fission in large nuclei such as uranium-235.
The most common isotope of uranium, U-238, does not split easily, but the
235 isotope does.
We induce fission by “tickling” the nucleus with a “thermal”
neutron. The
neutron has to have the right kinetic energy:
·
Too little kinetic energy means that the neutron will bounce off the
nucleus;
·
Too much kinetic energy means that the neutron will go right through the
nucleus.
·
Just right means that the neutron will be
captured by the strong force, which is attractive between nucleons. The
neutron gives the nucleus enough energy to resonate, and this will make the
nucleus neck as shown above
The
tickled nucleus flies
apart into a number of fragments, leaving
on average three
neutrons left over.
These too are able to tickle other nuclei and make them split.
Each neutron spawns three more neutrons in each fission, so we get a
chain
reaction.

There
is a mass defect in the products of the fission so energy is given out. In an uncontrolled chain reaction, the energy is given
out in the form of a violent explosion, which is many times more powerful than
the explosive decomposition of TNT. In
an atomic bomb, the mass that is converted to energy is about 20 grams.
The
daughter fragments may well be highly unstable, and decay by radioactivity.
These form the dangerous
fall-out
of an atomic bomb detonation, or the
waste
from a nuclear power station.
Either way, they form some of the nastiest muck known to mankind.
|
|

A
common bear trap is to say that nuclei are smashed to pieces by neutrons.
The neutrons tickle the nucleus; they do not hammer it.
Some students confuse fission and fusion and use the “fussion”. It will be marked wrong in the exam, so don’t.
Fusion
Fusion means joining nuclei together, every alchemist’s dream.
It is easier said than done. The
idea is that
light nuclei are joined
together, increasing the binding energy per
nucleon. This will result in lots of energy being given out.
A possible reaction is:
It
is not simply a case of sticking some deuterium and tritium together and shaking
it up. Each nucleus has to have
sufficient energy to:
·
Overcome electrostatic repulsion from the protons
·
Overcome the repulsive strong force which is found outside the region of
the strong force.
This
means that the gases have to be heated to a very high temperature, 100 million
Kelvin. As all matter at this
temperature exists as an ionised gas (plasma), it has to be confined in a very
small space by powerful magnetic fields. Fusion
has occurred, but the energy put in to cook the gases enough to make them fuse
is far greater than the energy got out by a fusion reaction.
Some
scientists claim to have found fusion at low temperatures.
They had a strange chemical reaction, but it was not fusion.
Fusion,
if it could be made to work, has a number of advantages over fission:
·
Greater power per kilogram of fuel used;
·
Raw materials are cheap and readily available
·
No radioactive elements are made by the reaction.
The
downside is that materials that make up the reactor will be irradiated with
neutrons which will make them radioactive.
| Question 6 |
Data to use: Mass of deuterium nucleus = 3.3425 ´ 10-27 kg Mass of tritium nucleus = 6.6425 ´ 10-27 kg Mass of helium nucleus = 6.6465 ´10-27 kg Mass of a neutron = 1.675 ´ 10-27 kg What is the energy in J and eV released in this reaction above? |
ANSW |
|
Summary Atomic Mass Unit: 1/12
th the mass of a carbon atom Mass
defect: Difference
between the mass of nucleons separately and together within a nucleus.
Difference between the two sides of a nuclear interaction equation. Energy
worked out by E = mc2.
Binding
Energy: Energy equivalent of the mass defect in a nucleus. Binding energy per nucleon increases in more stable nuclei.
Fission Splitting
of a nucleus. Rarely
spontaneous. Occurs after the
nucleus has been tickled with a neutron Fusion Joining
together of two light nuclei to make a heavier nucleus. |
| Presentations | |||
| Fission and Fusion | |||
|
Now try the Topic Quiz |
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