Answer 4_11_4

  Given this data:

Mass of aluminium nucleus = 28.97330 u

Mass of silicon nucleus = 28.96880 u

Mass of beta particle (electron) = 0.000549 u

Mass of electron antineutrino = 0

 

What is energy given out by this decay in MeV?  What form does it take?                          

 

Mass on right hand side = 28.96880 u + 0.000549 u + 0 = 28.969349 u (P)

 

Mass defect = 28.97330 u - 28.969349 u = 0.0039510 u (P)

 

Energy = 931.5 ´ 0.0039510 u = 3.68 MeV (P)

 

Energy is kinetic.  (P)

 

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