Answer 4_11_4
|
Given this
data: Mass of aluminium nucleus = 28.97330 u Mass of silicon nucleus = 28.96880 u Mass of beta particle (electron) = 0.000549 u Mass of electron antineutrino = 0 What is energy given out by this decay in MeV?
What form does it take?
|
|
Mass on right hand side = 28.96880 u + 0.000549 u + 0 = 28.969349 u (P) |
|
Mass defect = 28.97330 u - 28.969349 u = 0.0039510 u (P) |
|
Energy = 931.5 ´ 0.0039510 u = 3.68
MeV (P) |
|
Energy is kinetic. (P) |