Answer 4_11_2

What is the binding energy of the helium atom whose mass defect is 0.030377 u?  

 

m = 0.030377 u ´ 1.661 ´ 10-27 kg = 5.046 ´ 10-27 kg (P)

 

E = mc2 = 5.046 ´ 10-27 kg ´ (3 ´ 108)2 = 4.541 ´ 10-12 J (P)

 

 

 

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