Answer 4_11_2
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What is the binding energy of the
helium atom whose mass defect is 0.030377 u?
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m = 0.030377 u ´ 1.661 ´ 10-27 kg =
5.046 ´ 10-27 kg (P) |
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E = mc2 =
5.046 ´ 10-27 kg ´ (3 ´ 108)2 = 4.541 ´ 10-12 J (P) |
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