A search coil has 2500 turns and an area of 1.5 ´ 10^-4 m². It is placed between the poles of a large horseshoe magnet.  It is rapidly pulled out of the field in a time of 0.30 s.  A datalogger records an average value for the emf of 0.75 V.  What is the flux density between the poles of the magnet?

Î = -N DF/Dt  (P) and DF = BDA (P)

0.75 = (-) 2500 ´ B ´ (0 - 1.5 ´ 10^-4 m²) (P)

                               0.3 s

B =      0.75 V ´ 0.3 s  (P)

       2500 ´ 1.5 ´ 10^-4 m²

B = 0.6 T (P)