Answer 4_10_5
|
The
coil in question 4 is now turned so that it makes an angle of 60 o
with the magnetic field lines. What
is the change in flux linkage?
|
|
Original flux linkage = 0.05 Wb (P) |
|
New flux linkage = 200
´ 2.5 ´ 10-3 T ´ 0.1 m2
´ sin 60 (P) |
|
= 0.05 Wb ´ 0.866 = 0.0433 Wb (P) |
|
DF =
0.0433 Wb – 0.05
Wb = - 6.7 ´ 10-3 Wb (PP) |