Topic 1  Circular Motion

Key Words

Angular speed, Radian, Centripetal, Acceleration, Force

In the exam, you are expected to understand the ideas of circular motion:

  • Angular speed, w, and its related equations

  • Use w = 2pf, w = v/r, and a = w2r = v2/r

  • Recall and use F = mv2/r

 

Motion in a Circle

The rules of circular motion help us to describe:

We have so far applied Newton’s Laws to motion in a straight line; the forces are pushing or pulling the object along in the direction of its travel.  What happens if we put a force perpendicular to the direction of motion?

Question 1

What is the path of an object which is thrown horizontally and allowed to fall?   Sketch the path of the falling object. 

ANSWER

The path is a parabola.

Now let us suppose that the force applied at 90o to the object was always at 90o.  This time the path would be circular:

In this case, the linear speed remains constant, but the direction is always changing.  This means that there is a change in velocity, hence acceleration.  Along with this come concepts that are important in circular motion, such as angular velocity.

Question 2

Why does an object going around in a circular path at a constant linear speed have acceleration? 

ANSWER

Consider an object going round in a circle of radius r.

We know that anything going round in a circle has a constant speed but a changing velocity.  This is because the direction is constantly changing.  If we alter the radius, the linear speed also changes, even though we have not changed the rate of turning.  So we have to think up another quantity that we can use to describe the rate of turning.  We use angular velocity, physics code w (omega, a Greek letter longō’), how big an angle is turned in one second.  We could use degrees per second, but instead we use another kind of angular measurement, the radian.

·       One radian is the angle that subtends an arc whose length is the same as the radius. 

·        q rad = s/r. 

·        We can easily work out that 1 rad » 57 o. 

·        1 revolution is 2p radians.

·        For small angles in radians, q » sin q » tan q.  This is another reason why radians are so useful.  It does not work for large angles in radians, nor does it work for degrees. 

·        In dimensional analysis the radian is a dimensionless unit.  In some texts, you may see it missed out altogether, although here we will always include it.

·        w rad s-1 is the angular velocity. w = 2pf Þ linear speed v = wr = 2pfr m/s.

·        The direction of the velocity is tangential.

 

Question 3

A train is travelling at 50 m/s round a curve of radius 6000 m.  What is its angular velocity?

ANSWER
Question 4

A washing machine spins its drum at 1200 rpm.  If the diameter of the drum is 35 cm, find:

(a)    the angular velocity of the tub;                                                                  

(b)   the linear speed of the rim of the tub. 

ANSWER

A common bear-trap is to fail to convert revolutions per minute to radians per second.  Divide the rpm by 60, then multiply the answer by 2p.

Centripetal Acceleration

We need to distinguish between an object spinning on its axis, and an object moving in a circular path.  We will consider the latter only.  The former situation is part of rotational dynamics.  You can read about the derivation of the relationship in any textbook, so we will not cover it here.

·        Acceleration is always towards the centre of the circle and is given by a = w2r.

·        We can write this as a = v2/r

Question 5

If a = w2r, show that a = v2/r

ANSWER

·        Where there is acceleration, there is a force.   We call the force centripetal force (NOT centrifugal force!), which is described by the formula:

F = mv2

    r

·        The force acts towards the centre of the circle.

This is the circular motion version of Newton II, since F = ma and a = v2/r.

Suppose we were to whirl a stone around on a string, the forces would be governed by the relationship above.  However, if the string were to snap, the stone would fly off in a straight line at a tangent to the circle (NOT straight out from the centre).  The following are other examples that obey this relationship:

Problem solving strategy

1.      State clearly what object is being considered.

2.      Draw a free body sketch of the object.

3.      Mark the weight of the object

4.      Mark in any points where the object touches anything else and the forces involved.

5.      Decide which direction you will call positive.

6.      Apply Newton II (F = ma).

 

Worked example

A mass of 0.300 kg is moving in a circular path of radius 0.80 m on a friction free table.  It is attached to a peg in the middle of the table in the centre of the circle.  Draw the free body diagram of the mass and find the force exerted by the string on the mass when the mass is moving at a constant speed of 3.45 m/s.

Free body diagram:

a = v2/r = (3.45 m/s)2 ¸ 0.8 m = 14.9 m/s2

            Þ F = ma = 0.300 kg ´ 14.9 m/s2 = 4.46 N. 

The string pulls the weight towards the middle of the circle.

 

Question 6

A stone of mass 0.50 kg is attached to an inextensible string and  whirled in a vertical circle of radius 0.98 m at a constant speed of 7.0 m/s.  Gravity g = 10 m/s2

(a) calculate the angular speed of the stone.         

(b) calculate the centripetal acceleration of the stone;

(c) the least tension in the string. (Hint: think which way gravity acts)

ANSWER

 

Summary
  • Angular speed is better measure than linear speed
  • Angular speed in radians per second
  • Physics code is w, units radians per second.
  • w = 2pf
  • Centripetal acceleration = w2r = 4p2f2r = v2/r
  • Centripetal force F = mv2/r

 

Now try the Topic Quiz Home Physics A2 Module 4