Vectors and Scalars

Key Words

Scalar, vector, addition, resolution

 
Scalars and Vectors

Central to the study of mechanics is the idea of the vector quantity that not only has a value, but direction as well.  Examples include:

  Any quantity that does not specify a direction is a scalar, examples of which include:

Vector

Scalar

Unit

Displacement

Distance

Metres (m)

Velocity

Speed

Metres per second (m/s)*

Acceleration

 

Metres per second2 (m/s2)

Momentum

 

Newton seconds (Ns)

Force

 

Newtons (N)

 

Work , Energy

Joules (J)

 

Voltage

Volts (V)

 

Temperature

Degrees Celsius (oC)

 

Frequency

Hertz (Hz)

Notice that the units are the same, regardless of whether they are vectors or scalars.

Note:

Why is Work a Scalar? Click HERE

 

Adding Vectors

If the force vectors of 3N and 4N are in the same direction, they simply add together.

The heavy arrow indicates the resultant force.

If the vectors are in opposite directions, we subtract.

We can see that the resultant is now just 1 N.

If the two vectors are at 90o use Pythagoras’ Theorem.

Resultant2 = 32 + 42 = 9 + 16 = 25.     

\ Resultant = Ö(25) = 5 N

To work out the angle we use the tan function:

                        tan q = ¾ = 0.75  Þ q = tan-1(0.75) = 36.9o

 

 

Question 1

What are the resultants of these vectors?

ANSWER
Question 2 What are the angles that the resultants make to the vertical in the previous question?  ANSWER
 
 
Resolution of Vectors

We can resolve any vector into two components at 90o to each other.  They are called the vertical and the horizontal components.

Consider a car going up a hill. 

The angle of the hill is q degrees.  We must note that the weight (given by the mass in kilograms × acceleration due to gravity) is always pointing vertically down.  Acceleration due to gravity can be taken as 10 m s-2 and the force of gravity is 10 N/kg.  We can resolve the vectors, remembering that the weight acting vertically is the resultant force.

Remember:

It is depressing how many students write weight in kilograms.  Watch out for this bear trap!

Vector calculations can be done using scale drawing.

 

Equilibrium for Coplanar Forces

Forces in equilibrium mean that they are balanced.  Coplanar forces act in the same plane.  Two balanced forces are equal in magnitude but opposite in direction to the other.

We can see easily from the free body diagram that the resultant force is zero

If we are considering three coplanar forces in equilibrium, use the triangle of forces rule:

 If 3 forces acting at a point can be represented in size or direction by the sides of a closed triangle, then the forces are in equilibrium, provided their directions can form a closed triangle.

This means that the forces can follow each other round a triangle

Notice how

In statics, remember that all forces add up to zero.  That does not mean that there are no forces;  the forces balance each other out.

Worked Example:

A 6.0 N weight is attached to a light string which is then tied to the midpoint of a second string of length 0.8 m.   This string is suspended from two fixed points which are on the same horizontal line 0.60 m apart.  The arrangement is shown below:  

What is the angle between the two halves of the string?  

What is the tension in each half of the string?

First of all, draw the forces and the directions:

The weight vector splits the set up into two right-angled triangles.

The horizontal components are equal and opposite, so cancel each other out.

The weight vector can be considered as the resultant of two downward vectors which add up the total downward force.  Since this is a symmetrical system, each vector is 3 N.

Each closed triangle looks like this:

Now we can find q, the angle with the vertical.  It is the opposite, and we know the hypotenuse, so we use the sine function

0.4 sin q = 0.3 

sin q = 0.3/0.4 = 0.75

q = sin-1 0.75 = 48.6o

We now can say that the angle between the two strings is 2 x 48.6 = 97.2o

We can now work out the tension:

The angle q is the adjacent, so we use the cosine function.

T cos 48.6 = 3N

T = 3N ÷ cos 48.6 = 3 N ÷ 0.661 = 4.54 N

At AS level, you are most likely to encounter symmetrical systems like this.  If the system is NOT symmetrical, don't panic.  Remember:

        

Presentations Vectors Forces and Equilibrium
Now try the Test Home  Unit 2 Physics AS