Vectors and Scalars
| Key Words Scalar, vector, addition, resolution |
acceleration,
force,
velocity.
energy
temperature.
Vector
|
Scalar
|
Unit
|
|
Displacement |
Distance |
Metres
(m) |
|
Velocity |
Speed |
Metres
per second (m/s)* |
|
Acceleration |
|
Metres
per second2 (m/s2) |
|
Momentum |
|
Newton
seconds (Ns) |
|
Force |
|
Newtons
(N) |
|
|
Work
, Energy |
Joules
(J) |
|
|
Voltage |
Volts
(V) |
|
|
Temperature |
Degrees
Celsius (oC) |
|
|
Frequency |
Hertz
(Hz) |
Notice
that the units are the same,
regardless of whether they are vectors or scalars.
Note:
Some vectors can be used as scalar quantities.
There are some scalar quantities, e.g. temperature, that have no vector equivalent.
The shorthand for metres per second is either written ms-1 or m/s. Either is acceptable.
Work is the product of two vectors (Work = Force × distance moved in direction of force) but it is a scalar. Click on the link below for an animation to show why. You will need Windows Media Player (or similar).
| Why is Work a Scalar? | Click HERE |
If the force vectors of 3N and 4N are in the same direction, they simply add together.

The
heavy arrow indicates the resultant
force.
If the vectors are in opposite directions, we subtract.

We can see that the resultant is now just 1 N.
If the two vectors are at 90o use Pythagoras’ Theorem.

Resultant2 = 32
+ 42 = 9 + 16 = 25.
\ Resultant = Ö(25) = 5 N
To
work out the angle we use the tan
function:
tan
q
= ¾ = 0.75 Þ
q
=
tan-1(0.75) = 36.9o

|
What are the resultants of these vectors? |
ANSWER | |
| Question 2 | What are the angles that the resultants make to the vertical in the previous question? | ANSWER |
We can resolve any vector into two components at 90o to each other. They are called the vertical and the horizontal components.

Fx
= F
cos
q
Fy = F sin q
Consider a car going up a hill.

The angle of the hill is q degrees. We must note that the weight (given by the mass in kilograms × acceleration due to gravity) is always pointing vertically down. Acceleration due to gravity can be taken as 10 m s-2 and the force of gravity is 10 N/kg. We can resolve the vectors, remembering that the weight acting vertically is the resultant force.
Remember:

Vector
calculations can be done using scale
drawing.
Use
a sharp pencil
Use
graph paper
Choose
a scale for both vectors and stick to it
Measure
the angles with a protractor.

Forces
in equilibrium mean that they are balanced. Coplanar forces
act in the same plane. Two balanced
forces are equal in magnitude but
opposite in direction to the other.

We can see easily from the free body diagram that the resultant force is zero.
If we are considering three coplanar forces in equilibrium, use the triangle of forces rule:
If
3 forces acting at a point can be represented in size or direction by the sides
of a closed triangle, then the forces are in equilibrium, provided their
directions can form a closed triangle.
This means that the forces can follow each other round a triangle

Notice
how
The
forces form into a closed triangle.
The
directions of the forces go round the triangle.
In
statics, remember that all forces add up to zero.
That does not mean that there are no forces; the forces balance each other out.
| Worked
Example:
A
6.0 N weight is attached to a light string which is then tied to the midpoint of
a second string of length 0.8 m. This
string is suspended from two fixed points which are on the same horizontal line
0.60 m apart. The arrangement is
shown below:
What is the angle between the two halves of the string? What is the tension in each half of the string? |
| First
of all, draw the forces and the directions:
The weight vector splits the set up into two right-angled triangles. The horizontal components are equal and opposite, so cancel each other out. The weight vector can be considered as the resultant of two downward vectors which add up the total downward force. Since this is a symmetrical system, each vector is 3 N. Each closed triangle looks like this:
|
| Now we can find q, the
angle with the vertical. It is the opposite, and we know the hypotenuse,
so we use the sine function.
0.4 sin q = 0.3 sin q = 0.3/0.4 = 0.75 q = sin-1 0.75 = 48.6o We now can say that the angle between the two strings is 2 x 48.6 = 97.2o |
| We can now work out
the tension:
The angle q is the adjacent, so we use the cosine function. T cos 48.6 = 3N T = 3N ÷ cos 48.6 = 3 N ÷ 0.661 = 4.54 N |
At AS level, you are most likely to encounter symmetrical systems like this. If the system is NOT symmetrical, don't panic. Remember:
The weight (downwards force) can be split into two force vectors. These add up to the weight.
The horizontal force vectors add up to zero.
If you are completely stuck, use accurate drawing! Whatever you do, don't leave a blank!

| Presentations | Vectors | Forces and Equilibrium | |||
| Now try the Test | Home | Unit 2 | Physics AS | ||