Particles, Antiparticles, and Photons
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Key Words Wave-Particle Duality, Photoelectric Effect, Photon, Quanta, Threshold Frequency, eV, Particles, antiparticles |
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In the exam you are expected to know :
Photon model of electromagnetic radiation, the Planck constant, Knowledge of annihilation and pair production processes and the respective energies involved. The use of |
Particles and Antiparticles
Particle
physics is concerned with fundamental particles, which means that the particles can't be
broken down any further.. It used
to be thought that protons, neutrons and electrons were the fundamental
particles of matter. However it has
been found that nucleons (proton and
neutron) are made up of smaller particles, so nucleons are now not fundamental.
Each particle has an antiparticle. However,
antiparticles are not found in normal matter, but arise in:
high-energy collision experiments,
interactions with cosmic rays,
radioactive decay.
We should note the following:
an antiparticle has the same mass as its particle,
a particle and its antiparticle have equal
but opposite charge
an unstable particle and its antiparticle have the same
lifetime.
some neutral
particles and their antiparticles are identical (e.g. photon and po
meson)
other neutral particles and antiparticles are not
identical.
Antiparticles can be made in
large quantities in accelerators, resulting from high-energy collisions. They have short lifetimes, about 10-10 s because
when they meet their equivalent particle, they annihilate
each other in a burst of energy. It
is even possible to make simple antiatoms.
It is thought that there is more matter than antimatter in the Universe. It is not impossible that antimatter exists in large quantities somewhere, and that there are antimatter stars and planets. None have yet been detected.
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Observing
Smaller and Smaller Objects
Whenever
we observe something, we need three different pieces of apparatus:
illumination
(some kind of radiation)
the
object under study

If
you read a book, your eyes detect the changes caused by the effect of ink on
paper (the object) in response to light (radiation).
However
the light is limited by its wavelength to resolving objects about 1
mm across.
Much less than that, then diffraction becomes important.
Waves will not travel through a gap less than a wavelength.
Light wavelengths cannot resolve
atoms. Shorter wavelengths can be
used but the eye cannot detect these.
X-rays can be used to resolve individual atoms
by X-ray crystallography.
The wave
properties of electrons can be harnessed in electron microscopy.
We can resolve the structure of individual molecules, but not the
structure of the atoms themselves.
Waves
can be thought of as particles
Particles
have wave properties
Energy
and mass are interchangeable, linked by Einstein’s equation E
= mc2.
The energy of a wave or particle is related to the wave frequency by Planck's Equation:
E = hf
E - energy (J), f - frequency (Hz), and h - Planck's constant (6.63 × 10-34 Js)
To resolve the structure of atoms we need a very powerful microscope, several metres long. This gives us very high-energy particles with a very short de Broglie wavelength. Louis de Broglie argued that if light and other radiations could be considered as waves with particle properties, it was entirely reasonable to state that particles could have wave properties. His experimental work led to the combination of the wave equation and Planck's equation:

We will discuss this more below.
The two pictures show a light microscope and an electron microscope.

Energies of particles are expressed in electron-volts
(eV) where:
1 eV = 1.6 x 10-19 J
To see various levels of detail requires the following kinds of particle energies
100 eV
- the electron cloud
around the nucleus
100 MeV (1 x 108eV) - the nucleus
itself
10 GeV (1 x 1010eV) - the
fine structure of the nucleus.
Therefore to resolve parts of the nucleus needs very high particle energies to gain short de Broglie wavelengths. However, there's a problem. At these energies the particles have an unfortunate habit in smashing up the nuclei; a bit like asking a bull for a commentary on fine antique porcelain.
| What is the energy in joules of the following electron energies? |
From these energies in joules,
we can work out the speeds at which the electrons travel using v2 = 2
Ek/m. Mass of an electron = 9.11 ×
10-31 kg.
| What is the speed of an electron at an energy of 100 eV and at 10 GeV? |
The last answer gives us a speed of an
electron that is faster than the speed of light. In fact we cannot go
faster than the speed of light. A different (and more complex) equation is
needed as the speed of the electron gets towards the speed of light.
We can also get short de Broglie
wavelengths using heavier particles like alpha particles.
Light
as a Particle?
Historically
there had been a lot of controversy about the wave nature of light, as
proposed by the Dutch physicist Hans Huygens, against the corpuscular model
as proposed by the headstrong Isaac Newton.
The concept of wave-particle
duality was the start of modern physics in the middle to late Nineteenth
Century.
·
Reflection
·
Refraction
·
Diffraction
· Polarisation
However it can also be shown to have particulate properties as well. Consider this model:

If we spray just a short burst, we get just a few spots on the screen:

The longer we spray, the more spots appear until the whole area is covered in paint:

When
using a spray can, we don’t notice any diffraction effects as the particles
pass through the stencil. Hardly
surprising as the paint droplets are particles, not waves.

The intensity of the image on a photographic plate increases the longer the paper is exposed for. That intensity is determined by the number of silver grains deposited. We see that the pattern of silver grains deposited is random. It seems that the light that deposited the grains was actually made of particles.
The debate raged on until the discovery in the late nineteenth century with the discovery of the photoelectric effect.
The Photoelectric Effect.
The
concept of wave-particle duality was
the start of modern physics in the middle to late Nineteenth Century.

1. We charge the electroscope with a negative charge.
2.
We expose
the reactive metal to light of a long wavelength, e.g. red.
3.
We
observe that there is no effect, however bright the light.
4.
We then
expose the metal to short wavelength light, e.g. UV.
5.
This time
we see that the gold leaf drops down, showing that the electroscope is losing
charge.
6.
It does
not matter how bright or dim the UV light is.
7.
No effect
was observed when the electroscope was positively charged.
The results were:
|
Metal |
X-rays |
Ultra-Violet |
Blue
Light |
Red
Light |
| Magnesium |
P |
O |
O |
O |
|
Zinc |
P |
P |
O |
O |
|
Sodium |
P |
P |
P |
O |
|
Caesium |
P |
P |
P |
P |
This
led to the conclusion that:
Electrons
were being knocked off. Reactive
metals have outer shell electrons that can be removed easily.
Red
light would not show this effect however bright it was.
So the amplitude of the light wave was not important.
Red light only worked for caesium, which is a very reactive
metal.
There
was a threshold frequency at
which this phenomenon started to occur.
Light waves with a frequency higher than this (shorter wavelength)
always showed the effect, whatever the brightness; light waves with a lower
frequency never showed it.
The
more reactive the metal, the lower was the threshold frequency.
This
indicated a particle behaviour to
light.
| Why do these results suggest that light is not a wave? |
These
findings led to the notion of light being tiny little packets of wave energy
called photons.
Further
work by Max Planck in 1900 produced the
Photon
Model of Electromagnetic Radiation. We
can sum this up in the following points:
Light
and other electromagnetic radiation is emitted in bursts of energy.
We say that it is quantised.
The
packets of energy, photons,
travel in straight lines.
When
an atom emits a photon its energy changes by an amount equal to the photon energy.
The
energy changes are discrete amounts or quanta.
The
frequency of the light and the energy are related by a simple equation:
[E – energy in J; h – Planck’s Constant; f – frequency of the radiation in Hz]
The
constant
h is Planck’s Constant with the value 6.6 ´ 10–34 Js (joule seconds, NOT
joules per second).
We
can combine the equation above with the wave equation:
E = hf and c = fl
Þ E = hc
l
| What is the photon energy of light wavelength 350 nm? |
The
joule is the SI unit for energy.
However atomic physicists find the joule far too big and clumsy.
(You would not measure the width of your desk in kilometres.)
So they use a unit called the
electron
volt (eV).
The
charge on an electron is 1.6 × 10-19 C, so 1 eV = 1.6 × 10-19 J.
| Convert
your answer to Question 2 to electron volts. |
Electron volts are almost always used in atomic and nuclear physics, but before
using equations like
E = hf, the energies MUST be converted to joules. This is a
very common bear trap.
| A photon has an energy of 10.3 eV. What is its wavelength? Where on the electromagnetic spectrum would this be? |
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