Answer to Question 10
Maximum Power of corrected eye = 55 D Power = 1/u + 1/0.02 55 = 1/u + 1/0.02 = 1/u + 50 1/u = 55 - 50 = 5 u = 0.2 m
Maximum Power of corrected eye = 55 D
Power = 1/u + 1/0.02
55 = 1/u + 1/0.02 = 1/u + 50
1/u = 55 - 50 = 5
u = 0.2 m
