Further Electronics Tutorial 1 -  Capacitors

Capacitors are short term charge stores that hold electrical energy in the form of an electric field They are used widely in electronic circuits.  They are at the heart of all electronic timing devices.  They also can act as back up power supplies to memory chips.  Another use is to smooth out the ripples from a power supply; in effect they are electrical springs.  They are also found in oscillators, signal generators, tone controls (filter circuits) to name a few.  A variable capacitor is used to tune radios.

   

At its simplest a capacitor consists of two metal plates separated by a layer of insulating material called a dielectric. 

 

  Capacitance is measured in units called farads (F). A farad is a very big unit, and we are much more likely to use microfarads (mF) or nanofarads (nF).  You may even see picofarads (pF)

  The symbol for a capacitor is shown below:

There are two types of capacitor, electrolytic and non-electrolytic

Electrolytic

Non electrolytic

Advantages:

  • High capacitance

  • Can have high working voltages.

Advantages:

  • Do not lose charge

  • Polarity does not matter

  • Stable up to 106 Hz (or more)

Disadvantages:

  • Polarity important

  • High leakage current

  • Not stable above 10 kHz

  • Can be damaged by AC

Disadvantages:

  • Low capacitance

 

Leakage Current

In an electrolytic capacitor there has to be a current to maintain the aluminium oxide layer.  This is about 1 mA.  Over a period of time the charge leaks away.  This is called the leakage current.  Also it is important that the polarity of the capacitor is correct, otherwise the aluminium oxide layer is not made and the component will conduct.  The resulting heating effect can result in the capacitor exploding.

 

 

Working Voltage

All capacitors have a maximum working voltage.  All insulators have a maximum voltage at which they will retain their insulating properties.  The breakdown voltage is quoted in units of volts per metre, so it is actually an electric field.  The breakdown voltage of air is 3000 V/mm, so a 5 mm gap will insulate up to 15 000 V. The actual voltage at which the breakdown occurs depends on the thickness of the material.  The thinner the material, the lower the voltage that is needed before sparking will occur.  If sparking occurs over a dielectric, then a hole will be burned in the dielectric and that is the end of the useful life for the capacitor.

 

Picture by Ethanbrodsky, Wikimedia Commons

 

In this picture you can see some blown capacitors in a computer power supply.  In the middle the case has actually blown off the component, showing its guts.  Three of its neighbours are decidedly swollen and were about to go.

 

 

Stability

As capacitors age, their values can change.  This too can lead to poor stability in circuits. 

 

 

Temperature Coefficient

Capacitors, especially electrolytic, can lose their capacitance, i.e. hold less charge, when they get hot.  The decrease in capacitance can change the characteristics of the circuit so much that it will not work properly.  Therefore it is essential that the temperature in which the circuit is going to operate at is taken into consideration when designing a circuit and choosing the components.

 

The experiment below shows what happens if a capacitor is cooled with a freezing spray.

 

 

The results are like this:

From this graph we can see that:

Other types of capacitor have a temperature at which their capacitance is at a maximum.  It falls away either side of the optimum.

 

 

Data Sheets

Electronic engineers need to know the specifications of the components they are going to use.  They refer to data sheets in catalogues, which give them all the information that they need to make a choice.  For capacitors, data sheets might include:

Value (pF)

Tolerance

(± %)

Working Voltage (V)

Temperature Coefficient (ppm/K)

Size

Thickness ´ diameter (mm)

Price (pence)

4.7

0.25

100

0

2.5  ´ 5

13

330

5

100

+350 to -1000

2.5  ´ 5

13

4700

10

100

± 100 000

2.5  ´ 8

13

22 000

-20 to +80

63

± 220 000

2.5  ´ 10

13

 

Click on the button to find out more about capacitors.  You won't need to know this for the AS exam, but you might be interested.

 

Physics of Capacitors

 

 

How a capacitor holds charge

Capacitance is defined as:

 

The charge required to cause unit potential difference in a conductor.

 

Capacitance is measured in units called farads (F) of which the definition is:

 

1 Farad is the capacitance of a conductor, which has potential difference of 1 volt when it carries a charge of 1 coulomb.

 

So we can write from this definition:

 

Capacitance (F) = Charge (C)

                                     Voltage (V)

 

In code, this is written:

                                               

 

[Q - charge in coulombs (C); C – capacitance in farads (F); V - potential difference in volts (V)]  

 

We can show the relationship between the voltage and the charge on the graph.

 

The charge is directly proportional to the current.  This means that it's a straight line, going through the origin.  This stands to reason - no voltage, no charge.

 

Question 1

Write down what is meant by the following terms: 

  • Dielectric

  • Farad

  • Working voltage

Answer

 

The voltage rises as we charge up a capacitor, and falls as the capacitor discharges.  The current falls from a high value as the capacitor charges up, and falls as it discharges.

 

 

If we connect a capacitor in series with a bulb:

We can say that a capacitor blocks d.c., but allows a.c. to flow.

 

The capacitor does NOT conduct electricity.  The "flow" of a.c. is due to the charge and discharge of the capacitor.

 

Question 2 

Why does a capacitor appear to allow ac to flow, but not dc? 

Answer
Question 3

What is the charge held by a 470 microfarad capacitor charged to a p.d. of 8.5 V?    

Answer

 

 

 

 

Capacitors in Series and Parallel

 

Parallel Capacitors

Here is a circuit consisting of two capacitors in parallel.  They have values C1 and C2 and are connected to a battery of voltage V.

 

 

  Ctot = C1 + C2

  This is true for any number of parallel capacitors, so

  Ctot = C1 + C2 + C3 + … + Cn

 

Worked Example

 

What is the single capacitor equivalent of this circuit below? What is the charge on each capacitor?

 

  • Use Ctot = C1 + C2 to get the capacitance

  • Use Q = CV to get the charge.

 Answer

Ctot = C1 + C2 = 4 mF + 6 mF = 10 mF

            Charge on C1 = 4 × 10-6 F × 12 V = 4.8 × 10-5 C = 48 mC

            Charge on C2 = 6 × 10-6 F × 12 V = 7.2 × 10-5 C = 72 mC

            Total charge = 48 mC + 72 mC = 120 mC

 

 

Question 4

What is the single capacitor equivalent of these parallel capacitors?

 

   

Answer

 

Series Capacitors

Here is a circuit consisting of two capacitors in series.  They have values C1 and C2 and are connected to a battery of voltage V.

 

 

 

  In any series circuit

Since Q = It, it is reasonable to say that the charge that has moved is the same all the way round.  If a number of electrons of total charge of Q crowds onto the negative plates of C2 then the same number of electrons are repelled away from the positive plates.  These crowd onto the negative plates of C1 and repel the same number away from the positive plates.

 

Now we know that V = Q/C and that Vtot = V1 + V2.  So we can write:

 

1   =  1   +    1

Ctot    C1       C2

This gives us a general relationship for any number of series capacitors:

 

1   =  1   +  1  +  1  +  …  +  1

Ctot   C1      C2     C3              Cn

 

We can tackle problems that involve both series and parallel capacitors in a similar way to the way we tackle problems with combined series and parallel arrays of resistors.

  Click HERE for a worked example.

 

Worked Example

What is the single capacitor equivalent of this circuit below?  What is the charge on each capacitor?  What are the voltmeter readings?

Use

  • 1/Ctot = 1/C1 + 1/C2
  • Voltages add up to the battery voltage.

Answer

Work out the total capacitance:

 

            1   =  1   + 1    =  _1 _  +  _1_   = 3 + 2 = _5 

            Ctot    C1    C2      4 mF      6 mF      12       12

        Þ Ctot = 12/5 = 2.4 mF     

 

Now we can work out the charge:

           

Q = CV = 2.4 mF x 12 V = 28.8 mC

 

Now work out the voltages

 

On capacitor 1, V = 28.8 ÷ 4 = 7.2 V

 

On capacitor 2, V = 28.8 ÷ 6 = 4.8 V

 

Voltages add up.  Battery voltage = 7.2 + 4.8 = 12.0 V (Kirchhoff II)

 

Question 5

What is the single capacitor equivalent of these series capacitors?

 

   

Answer

 

When you tackle problems involving both series and parallel capacitors in the same circuit, you may find it helpful to adopt the following problem solving strategy:

Click on the button to see how these equations are derived.

 

Derivation

 

The picture shows a variable capacitor used to tune a radio.

 

 

Summary

  • Capacitors are charge stores

  • Electrolytic capacitors hold much more charge than non-electrolytic.

  • Capacitors are measured in farads.

  • Capacitors have characteristics like:

  • Leakage Current

  • Working Voltage

  • Temperature Coefficient

 

Capacitors in Series and Parallel

  • Ctot = C1 + C2 (Parallel)

      1   =  1   +    1 (Series)

     Ctot    C1       C2

 

Presentation

Capacitors

 

Useful Websites

http://www.st-andrews.ac.uk/~www_pa/Scots_Guide/info/comp/comp.htm

http://www.s-cool.co.uk/topic_index.asp?subject_id=2

 

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