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It is important to understand that radioactive decay is entirely a random and unpredictable process. If we look at any one nucleus, it might decay in ten seconds or ten million years. There is no way of telling when the decay will happen, and there is certainly no way of speeding up the process. Remember that chemical reactions involve the outer shell electrons; radioactive decay involves the nucleus.
However
when we have many millions of millions of nuclei, we can apply statistical
models of probability.
The
rate of disintegration of any nuclide
at any time is directly proportional to the number of atoms left at the time:

This
is calculus notation for rate of change in number.
The
minus sign tells us that N decreases
as time increases.
There
is a constant of proportionality called the radioactive decay constant, which is given the physics code l
(greek letter ‘l’,
not to be confused with wavelength), and has the units s-1.
So we can write:

The
radioactive decay constant is defined as the fraction of the total number of nuclei present that decays per unit
time, provided that the time interval is small.
For nuclides with relatively long half-lives, the decay constant will
have units “per second”. However
some very unstable nuclides decay in microseconds, so the decay constant would
have to be “per nanosecond”.
Example
| 0.25 kg radon-226 emits alpha particles at a measured rate of 9 × 1012 s-1. What is the decay constant of radium? (No of atoms in a mole = 6 × 1023) |
|
Work
out the number of particles: 0.250 × 6 × 1023 = 6.64 × 1023
atoms 0.226 |
|
We
know that the rate of decay is 9 × 1012 s-1. So we use DN/Dt
= -lN
- 9 × 1012 s-1 = -l
× 6.64 × 1023 l
= 1.36 × 10-11 s-1 (The minus sign indicates a decay) |
The unit Becquerel (Bq) is often used. 1 Bq = 1 count per second.
Over longer periods of time, the relationship above does not hold. It can be shown by calculus methods (which you are not expected to know), that the decay follows the relationship:

[N
– no of nuclei; N0 – original number of nuclei; e – exponential number, 2.718…; l - decay constant (s-1); t
– time (s)]
This relationship is described as an exponential decay and the graph looks like this:

We
should note the following:
The
rate of decay represents the number
of atoms remaining. So we
can use this graph for representation of the count rate, or ionisation
current.
The
rate of decay is the number of disintegrations
per second, or the activity.
It is measured in Becquerels (Bq).
1
Bq = 1 disintegration per second.
Notice
that the horizontal axis is calibrated in periods of time in which the decay
goes from an initial value to half that value.
This period is called the
half-life.
The formal definition of half-life is the time taken for the activity of
a sample to decrease to half some initial value.
After 1 half life the activity is 50 %, between 1 and 2 half lives it
falls from 50 % to 25 % and so on. If
we have a whole number of half-lives, we can do an iterative calculation of the
fraction remaining, i.e. ½, ¼, 1/8, etc.
We
can relate the half-life to the decay constant:
By definition

The formula is N = N0e-lt. Rearranging gives us

T1/2 (pronounced "T-half") is the physics code for half-life.

This
will work for any units of time, although we need to be consistent.
To
work with these relationships, you must be familiar with the concept of logarithms
(a way of expressing a number as a power of 10 or e).
You will see logarithms expressed as ‘lg’ or log10, which
means log to the base 10, or ‘ln’ or loge, log to the base e.
The number e is the exponential number, 2.718...
The latter is known as natural
logarithms, which are at the heart of exponential functions.
Example
|
A
radiographer has calculated that a patient is to be injected with 1 ´ 1018 atoms of iodine 131 to
monitor thyroid activity. The
half-life is 8 days. Calculate: (a)
the
radioactive decay constant (b)
the
initial activity (c)
the
number of undecayed atoms of iodine 131 after 24 days. (d) The total activity after 3 days. |
|
(a)
We need to use T1/2 = 0.693
l
we
need to convert the 8 days into seconds.
Þ l = 0.693 _
= 1.00 ´ 10-6
s-1 8 ´ 86400 |
|
(b)
Use DN
= - lN =
1.00 ´ 10-6 s-1 ´ 1 ´
1018 = 1 ´ 1012
Bq Dt |
|
(c) 24 days is 3 half-lives. Therefore
the number atoms remaining undecayed is 1/8 of the original.
N = 1 ´ 1018 ¸ 8 = 1.25 ´ 1017 |
|
(d)
3 is not so easy. We use A
= A0e-lt Þ
A = 1 ´
1012 Bq ´ e-(1.00
´
10-6 s-1 ´
3 ´
86400s) Þ
A = 1 ´
1012 Bq ´ e-(0.2592) = 1 ´ 1012 Bq ´ 0.772 = 7.72 ´ 1011 Bq. |
[Alternative method] If you are not so confident in the use of the natural logarithm, you can work out the number of half-lives a particular time gives. In this case 3 days = 3/8 of a half life.
Activity
= 1 ´ 1012 ´ 1/23/8 = 1 ´ 1012 ´ 1/1.30 = 7.7 ´
1011 Bq
This is a perfectly valid alternative approach.
The half-life has important implications for the storage of radioactive waste. Radioactive waste is some of the nastiest muck known to man, so it has to be stored carefully. Isotopes with a short half-life have intense activities, whereas those with a long half-life have lower activities, but it takes much longer for the activity to decay to a reasonable level. Either way, it’s not very nice.
Even
when there have been several half-lives, there remains quite a considerable
activity. If in our example above
the activity had decayed to 1/1000th of its original value, we would
still have 109 disintegrations per second, which is quite a lot.
Another
use of the decay equations is in
radioactive
dating. Isotopes used are
carbon-14, rubidium-87, and hydrogen 3.
Summary
Radioactive
decays are random. Rate
of decay depends on the number of atoms left The
probability of any one nucleus decaying in any one second is the decay
constant Decay
constant is given the code l DN
= -lN Dt
Over
a longer period of time, decay is exponential. N
= No e-lt Half
life is the time taken for ½ the remaining atoms to decay T1/2
= 0.693
l |