Topic
11
555 Timer Circuit
|
You
will learn to:
-
Draw,
recognise and use the circuit diagram for a 555 monostable, treating
it as a functional block
-
Calculate
the time period, using T = 1.1.RC;
-
Draw,
recognise and use the circuit diagram for a 555 astable, treating it
as a functional block.
-
Calculate
frequency using f = __1.44__
(RA + 2RB)C
|
The
555
timer is a popular circuit used for timing purposes.
It can be used in:
The 555 timer is a small 8-pin
integrated circuit, and we can add resistors and capacitors to an external
circuit to make it act as a monostable or an astable.
|
Parameter
|
CMOS
|
Bipolar
|
|
|
100 mA
|
200 mA
|
|
Voltage range
|
2 – 15 V
|
4.5 – 4.5 V
|
|
Operating current
|
120 mA
|
10 mA
|
The pin arrangement (pin-out) is shown
below:

555
timer in Monostable Mode
The
555 timer in monostable mode is constructed using the circuit shown in this
diagram.

The
circuit will give a single output pulse like this:
The
components R
and C
determine the time period T
of the output pulse.
- When
the push switch S
is closed and released, the voltage at pin 2 goes from high to low to high
again.
- This
triggers the output to go to high. Pin 7 is also disconnected from zero.
- When
the voltage across C
gets to about 2/3 of the supply voltage, the output goes low.
- The
period of the pulse is given by a simple relationship:
T
»
1.1 RC.
- Once
triggered, the circuit cannot be re-triggered to extend the period T.
Click
HERE
for a worked example.
In
using a 555-timer we need to be aware that the circuit has one or two little
quirks:
- The
trigger period must be less than the output pulse.
- The
5 nF capacitor connected to pin 5 is needed to prevent false triggering.
- The
circuit can produce brief dips in the voltage of the supply. This can
be countered by placing a large value capacitor across the supply rails.
This eliminates the voltage change (called decoupling).
- If
electrolytic capacitors are used in the RC circuit, leakage currents and
poor tolerances can result in the output pulse being greatly at variance
with the value predicted by the formula.
The
555 timer can be wired up to produce a train of pulses by ensuring that the
circuit is astable, which means that
it is not in a stable state. We can
make astable circuits from other components, but the 555 timer gives a train of
digital pulses. The diagram
shows the circuit.

The
output of the circuit is a square wave, as shown.

We
need to consider some definitions:
- The
mark
time [t(H] is the time at which the output is a 1. t(H)=
0.7(RA + RB)C
- The
space
time [t(L)] is the time at which the output is a 0. t(L)
= 0.7 RBC
- The
mark
to space ratio = mark time ÷ space time.
- The
astable
period T
is the time taken for one complete cycle, the mark and the space times added
together. T
= mark + space = t(L)
+ t(H).
- The
frequency
= 1 ÷ period.
f
= ____1.4_____
(R1
+ 2R2)C
The
time t(H) will be longer than t(L), unless R1 is very small compared to R2.
If this is the case, then t(H) will be approximately equal to t(L), but not
quite equal. We can say to a first approximation that the mark to space
ratio is 1. This will result in a square wave output.
Click
HERE
for a worked example.
|
Summary
Astable
·
f =
__1.44__
(RA + 2RB)C
- Mark
time tH = 0.7(RA + RB)C
- Space
time tL = 0.7 RBC
|
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Module 1 Activities