Topic 11  555 Timer Circuit

You will learn to:

  •  Draw, recognise and use the circuit diagram for a 555 monostable, treating it as a functional block

  • Calculate the time period, using T = 1.1.RC;

  • Draw, recognise and use the circuit diagram for a 555 astable, treating it as a functional block.

  • Calculate frequency using f =  __1.44__  

           (RA + 2RB)C

  • Calculate the time that the output is low (tL) using tL = 0.7 RBC.

  • Calculate the time that the output is high (tH) = tH = 0.7(RA + RB)C.

The 555 timer is a popular circuit used for timing purposes.  It can be used in:

  The 555 timer is a small 8-pin integrated circuit, and we can add resistors and capacitors to an external circuit to make it act as a monostable or an astable. 

Parameter

CMOS

Bipolar

Maximum current

100 mA

200 mA

Voltage range

2 – 15 V

4.5 – 4.5 V

Operating current

120 mA

10 mA

  The pin arrangement (pin-out) is shown below:

555 timer in Monostable Mode

The 555 timer in monostable mode is constructed using the circuit shown in this diagram.

The circuit will give a single output pulse like this:

The components R and C determine the time period T of the output pulse. 

T » 1.1 RC.

 Click HERE for a worked example.

In using a 555-timer we need to be aware that the circuit has one or two little quirks:

 

555 timer in Astable Mode

The 555 timer can be wired up to produce a train of pulses by ensuring that the circuit is astable, which means that it is not in a stable state.  We can make astable circuits from other components, but the 555 timer gives a train of digital pulses. The diagram shows the circuit.

The output of the circuit is a square wave, as shown.

 

We need to consider some definitions:

                        f =  ____1.4_____

                               (R1 + 2R2)C

  The time t(H) will be longer than t(L), unless R1 is very small compared to R2.  If this is the case, then t(H) will be approximately equal to t(L), but not quite equal.  We can say to a first approximation that the mark to space ratio is 1.  This will result in a square wave output.

 Click HERE for a worked example.

Summary

Monostable

  • T = 1.1.RC

 

Astable

·      f =  __1.44__  

                       (RA + 2RB)C

  • Mark time tH = 0.7(RA + RB)C
  • Space time tL = 0.7 RBC

·        Mark to space ratio = mark time ¸ space time

·        T = mark + space = tL + tH.

 

Useful Website

http://www.doctronics.co.uk/555.htm

also for data specifications, go to:

http://www.datasheetarchive.com/

 

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