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At the end of this Topic you should be able to:
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This kind of amplifier is used in digital to analogue conversion, or as a mixer in an audio system.
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You can see that this circuit is like an inverting amplifier. It uses negative feedback into the inverting input, but instead of one input, there are three inputs.
Question 1. What does this circuit remind you of? ANSWER
Question 2 What does this mean in simple terms?
So we can use Ohm’s law to rewrite this in terms of voltage and resistance.
Question 3
Notice that in the next step we use the minus sign because X is at a virtual earth so we have to climb the potential difference hill to get to Vout. This is Kirchhoff II.
-Vout = V1 + V2 + V3 therefore Vout = - Rf (V1 + V2 + V3)
Rf
R1
R2 R3
R1 R2
R3
If
the values of all the resistors are the same:
Vout = -(V1 + V2 + V3)
Summing
amplifiers are found in mixing desks
which add together the inputs from several different audio sources.
Question
4 Can you explain why the statement Vout = -(V1 + V2
+ V3) is true? ANSWER
Digital
to Analogue Conversion
There
are many occasions in which digital signals are converted to analogue.
Computers know two states, ON and OFF, but the signals that we pick up
and use are analogue. So the output of a computer (or a CD deck) is pretty
meaningless without some kind of digital
to analogue conversion.

Since
the inverting input is a virtual earth, we can say that the total current Itot
is given by:
Vout = - Itot Rf
= - Rf(I1 + I2
+ I3 + I4)
= - Rf(V1 + V2
+ V3 + V4)
R
2R 4R
8R
For every change in one bit, there is a voltage change of 0.0625 V. For an eight bit word it is 1/256 = 0.00390625 V. For a 16 bit word the smallest voltage change is 1/216 = 1/65536 = 0.0000152 V. You can see that the more bits there are, the smaller the voltage change per bit, leading to greater resolution.
Question 5
Question 6 Suppose V = 5 volts and R = 10 k and Rf = 1k. Use these to work out Vout for the binary word 1101. ANSWER


